Subtract to Date

Overview

The subtract-to-date transformation subtracts a specified amount of time from a date.

subtract-to-date(<variable>, amount=0, unit="days")

Parameter	Type	Required	Default	Description
`variable`	date	Yes	-	The date to subtract time from
`amount`	number	No	`0`	The amount to subtract
`unit`	string	No	`"days"`	Unit of time: `"days"`, `"hours"`, `"minutes"`, `"seconds"`, `"months"`, `"years"`

subtract-to-date(<variable>, amount=7, unit="days")
subtract-to-date(<variable>, 30, "days")